My apologies if my post is confused but I am a newcomer to this field, so the question may be trivial.
First of all, I am solely concerned with fine art and I assume that a "digital sculpture" will be made of one material - at least for the time being. For an application I am developing I need to find the equivalent, for a digital sculpture, of the number of pixels that is used in say a photograph to define its "size". Is there such an equivalent in a 3d printed sculpture? Do the software tools give you the total volume occupied by the sculpture (in that case cm^3 could be a good unit of measure)? Once you know the material, could one use grams instead? Does the software that drives a 3d printer give you the weight of the object?
Volume is better in that it is material-independent, but I am open to any other suggestion. Also, the volume should not include the empty space(s) *within* the sculpture but be the actual volume of the material being used. Again, do software tools like zbrush or mudbox give you this figure?
Thank you for your patience and again, sorry if the question is silly.
Any comment will be appreciated
Cheers
Marco
First of all, I am solely concerned with fine art and I assume that a "digital sculpture" will be made of one material - at least for the time being. For an application I am developing I need to find the equivalent, for a digital sculpture, of the number of pixels that is used in say a photograph to define its "size". Is there such an equivalent in a 3d printed sculpture? Do the software tools give you the total volume occupied by the sculpture (in that case cm^3 could be a good unit of measure)? Once you know the material, could one use grams instead? Does the software that drives a 3d printer give you the weight of the object?
Volume is better in that it is material-independent, but I am open to any other suggestion. Also, the volume should not include the empty space(s) *within* the sculpture but be the actual volume of the material being used. Again, do software tools like zbrush or mudbox give you this figure?
Thank you for your patience and again, sorry if the question is silly.
Any comment will be appreciated
Cheers
Marco
Comment